Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 60 minutes earlier than Car 2 and averages 40 mph and if Car 2 averages 50 mph, how far apart will they be after Car 1 has traveled 3.5 hours?
Accepted Solution
A:
Answer:The two cars will be almost 188 miles far from each other.Step-by-step explanation:Travel Time for Car 1 = t = 3.5 hoursTravel time for Car 2 = t-1 = 3.5 - 1 = 2.5 hoursAverage speed of car 1 = 40 mphAverage speed of car 2 = 50 mphDistance traveled by Car 1 = 40*3.5 = 140 milesDistance Traveled by Car 2 = 50*2.5 = 125 milesAs both the roads are at a 90 degree angle. The path of the two cars and the joining line of their final position forms a right angle triangle where:altitude = a = 140base = b = 125Distance of cars after 3.5 hours = c = ?According to Pythagoras theorem:c^2 = a^2 + b^2c^2 = 140² + 125²c² = 19600+15625c = √35225c = 187.68Almost 188 miles.